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Sunoco Gt100 + Ecu


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Guest 300+_T5R_855

Isn't CR is is how much the air compresses, ? Like if you take 10 liters to 1 liter thats a 10:1 So if you do it at 20000 psi its still 10:1 just a lot more mass, the ratio stays the same ?

or am i wrong?

Doesn't work that way. Your confusing A/F ratio with compression ratio.

Why bother to have a turbo then?

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Isn't CR is is how much the air compresses, ? Like if you take 10 liters to 1 liter thats a 10:1 So if you do it at 20000 psi its still 10:1 just a lot more mass, the ratio stays the same ?

or am i wrong?

LOL this topic. 85% of people exited to google not back to the site ;)

I am sure CJ was just thinking of something else. We all have those days.

Doesn't work that way. Your confusing A/F ratio with compression ratio.

Why bother to have a turbo then?

No. Your confusing chapstick with compression ratio. If you want I will lock this topic for you.

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Guest 300+_T5R_855

<Takes popcorn out of microwave... reclines chair>

Regardless of air density due to altitude it still shows different CR at any given level under different amounts of boost.

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Regardless of air density due to altitude it still shows different CR at any given level under different amounts of boost.

Alright kack mopper. IF you want to change this we can. But the engines compression ratio is static. Were not talking boost ratio, fuel ratio, farts to mpg ratio. A cylinders compression ratio is static

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Guest 300+_T5R_855

Alright kack mopper. IF you want to change this we can. But the engines compression ratio is static. Were not talking boost ratio, fuel ratio, farts to mpg ratio. A cylinders compression ratio is static

engine logics

Change any of these numbers, and the point at which the compressor runs at changes. More engine rpm means more air flow, so the operating point moves to the right. Colder intake temperatures means more pounds of air which moves our point to the right. Raising the boost probably means more air into the cylinders, but also the compression ratio goes up so our point definitely moves up and should move right. And so on.

I must be missing something.

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Guest 300+_T5R_855

.......

I am almost too tired..... almost!

Go read your own post again

If you have 10:1 CR at 14.7 atmospheric pressure without boost and you add 15psi boost you in effect have 29.7 absolute psi. This in essence doubles your volume in the same compression chamber. Which increases the CR to 20:1 It is call dynamic compression ratio.

Schools out.

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If you have 10:1 CR at 14.7 atmospheric pressure without boost and you add 15psi boost you in effect have 29.7 absolute psi. This in essence doubles your volume in the same compression chamber. Which increases the CR to 20:1 It is call dynamic compression ratio.

Schools out.

Worst post yet. Try again

The compression ratio is a single number that can be used to predict the performance of any internal-combustion engine. It is a ratio between the volume of a combustion chamber and cylinder when the piston is at the bottom of its stroke, and the volume when the piston is at the top of its stroke. The higher the compression ratio, the more mechanical energy an engine can squeeze from its air-fuel mixture. Higher compression ratios, however, also make detonation more likely.

The ratio is calculated by the following formula:

\mbox{CR} = \frac { ( \pi b^2 s) / 4 + V_c } {V_c}, where

b = cylinder bore (diameter)

s = piston stroke length

Volume, not mass. Schools in bitch

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Guest 300+_T5R_855

Worst post yet. Try again

The compression ratio is a single number that can be used to predict the performance of any internal-combustion engine. It is a ratio between the volume of a combustion chamber and cylinder when the piston is at the bottom of its stroke, and the volume when the piston is at the top of its stroke. The higher the compression ratio, the more mechanical energy an engine can squeeze from its air-fuel mixture. Higher compression ratios, however, also make detonation more likely.

The ratio is calculated by the following formula:

\mbox{CR} = \frac { ( \pi b^2 s) / 4 + V_c } {V_c}, where

b = cylinder bore (diameter)

s = piston stroke length

Volume, not mass.

So the volume doesn't change under boost. This is a blown engine not a N/A engine. Volume is not static.

Wrong answer Che' You don't get to go to the lightning round

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